3t^2-20t=100

Solution for 3t^2-20t=100 equation:

3t^2-20t=100

We move all terms to the left:

3t^2-20t-(100)=0

a = 3; b = -20; c = -100;
Δ = b2-4ac
Δ = -202-4·3·(-100)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*3}=\frac{-20}{6}
=-3+1/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*3}=\frac{60}{6}
=10
$